U3AOS1 Topic 5: Connected Bodies

Definition


Systems in which two or more items are connected in a way that makes their motions reliant on one another are referred to as connected bodies, sometimes known as connected particles. This idea is fundamental to mechanics, especially when applying Newton's principles to analyze forces and motion.


Several bodies that link up in a way that allows them to move together and affect one another's motion are referred to as connected bodies in physics. These connections might be elastic (like threads or ropes), rigid (like rods or bars), or a mix of the two. According to the laws of mechanics, the link insures that the motion of one body influences the motion of the others.


Most commonly, pulleys, tow bars, ropes, or strings are used to connect connected bodies. For example, in a basic system with two masses linked by a string over a pulley, the movement of one mass has an immediate effect on the other. Connected motion can be defined by this mutual dependence.



Mechanics of Connected Bodies


The mechanics of connected bodies often involve analyzing the forces acting on each body, such as tension in the string and gravitational forces. The key principles include:


Pulleys

The mechanics of connected bodies often involve analyzing the forces acting on each body, such as tension in the string and gravitational forces. The key principles include:


Equations of Motion


Free-body diagrams are essential tools for visualizing the forces acting on each body. By applying Newton's second law to these diagrams, we can derive the equations of motion. For example, in an Atwood machine, two masses are connected by a string over a pulley.


When the bodies move vertically,

\[ m_{1} g − T = m_{1} a \]

\[ T - m_{2} g = m_{2} a \]

Here, $ T $ is the tension in the string, $ g $ is the acceleration due to gravity, and $ a $ is the acceleration of the system.


By adding both equations, we get,

\[ m_{1} g - m_{2} g = m_{1} a + m_{2} a \]

\[ (m_{1} - m_{2}) g = (m_{1} + m_{2}) a \]

\[ a = \frac{(m_{1} - m_{2}) g}{m_{1} + m_{2}} \]


Putting the value 'a' in equation $ T - m_{2} g = m_{2} a $ gives:

\[ T = \frac{2 m_{1} m_{2} g}{m_{1} + m_{2}} \]

When the body moves vertically and the other moves horizontally:

\[ m_{1} g - T = m_{1} a \]

\[ T = m_{2} a \]


By putting the value of T in above equation:

\[ m_{1} g - m_{2} a = m_{1} a \]

\[ m_{1} g = (m_{1} + m_{2}) a \]

\[ a = \frac{m_{1} g}{m_{1} + m_{2}} \]

And thus,

\[ T = \frac{m_{1} m_{2} g}{m_{1} + m_{2}} \]


Application


Connected bodies are widely used in various fields, including engineering and physics. They are essential in designing mechanical systems such as elevators, cranes, and conveyor belts. Understanding the motion of connected bodies helps in optimizing these systems for efficiency and safety.


Understanding connected bodies is crucial in various fields, including mechanical engineering, robotics, and biomechanics.


Mechanical Engineering: Engineers use the principles of connected bodies to design machines and structures that can withstand forces and perform specific functions. This includes everything from simple tools to complex machinery like engines and cranes.


Robotics: In robotics, the analysis of connected bodies helps in designing robotic arms and other mechanisms that require precise control of motion and force distribution.


Biomechanics: The human body itself can be analyzed as a system of connected bodies, where bones act as rigid links and muscles as flexible connectors. Understanding this system is essential for fields like prosthetics and physical therapy.


Creating a free-body diagram


Creating a free-body diagram involves several steps. Follow these steps to ensure accuracy:


  1. Identify the Object of Interest.


  1. Sketch the object being analyzed in isolation.


  1. Determine All Forces Acting on the Object:

Consider all forces, including gravity, normal force, friction, tension, and applied forces.


  1. Draw the Object in Isolation:

Represent the object with a simple shape, like a box or a dot.


  1. Represent Forces with Arrows:

Draw arrows emanating from the object's center to show the direction and relative magnitude of each force. Label each arrow with the appropriate force symbol (e.g., Fg​ for gravitational force).


  1. Use Equations to Represent Forces:

For each force, write the corresponding equation. For example:

Apply Newton's second law to set up equations of motion.

For a body in equilibrium: $ \sum F_{x} = 0 $ and $ \sum F_{y} = 0 $

For a body in motion: $ \sum F = ma $


Analysis of Forces


In problems involving connected bodies, forces can act vertically, horizontally, or along inclined planes. Each scenario requires a specific approach to analyzing the forces and resulting accelerations. For inclined planes, the gravitational component along the plane and the normal force must be considered.


Mathematical Analysis


To analyze connected bodies, one must apply the principles of Newtonian mechanics, which involve forces, torques, and the resulting accelerations. Key equations and concepts include:


Newton's Laws of Motion: These laws describe the relationship between the motion of an object and the forces acting on it. For connected bodies, Newton's Second Law ($ F = ma $) is particularly important, as it allows for the calculation of acceleration when multiple forces are acting on a system.


Equilibrium Conditions: For a system of connected bodies in equilibrium, the sum of forces and the sum of torques must be zero. This condition is used to solve for unknown forces or tensions in the connections.

Kinematic Constraints: These constraints describe the geometric relationships between the motions of connected bodies. For example, in a pulley system, the movement of one part of the rope determines the movement of other parts.


Conclusion

The study of connected bodies is fundamental in mechanics. It involves understanding the interactions between linked objects and applying Newton's laws to predict their motion. By mastering these principles, one can solve complex problems involving multiple interconnected components in both academic and real-world applications.

Example 1

Two blocks, A and B, of masses mA​=2kg and mB​=3kg respectively, are connected by a light string over a frictionless pulley. If block A is on a frictionless table and block B is hanging off the edge, find the acceleration of the system and the tension in the string.

Let T be the tension in the string and a be the acceleration of the system.
For block A: T=mA​a
For block B: mB​g−T=mB​a
Combining the equations: T=mA​a mB​g−T=mB​a

Substitute T from the first equation into the second: mB​g−mA​a=mB​a a(mA​+mB​)
=mB​g a=mA​+mB​mB​g​=2+33×9.8​=529.4​
=5.88m/s2
Now, find the tension: T=mA​a=2×5.88
=11.76N



Example 2

A 5 kg block on a table is connected to a 3 kg block hanging off the side of the table by a light string over a frictionless pulley. The coefficient of kinetic friction between the 5 kg block and the table is 0.2. Find the acceleration of the system and the tension in the string.

m1​=5kg,    m2​=3kg,     μk​=0.2
Let T be the tension and a be the acceleration.
For block on the table: T−μk​m1​g
=m1​a T−0.2×5×9.8
=5a T−9.8
=5a

Combine the equations: T−9.8=5a, 29.4−T=3a
Add these two equations: 29.4−9.8=8a
19.6=8a
a=819.6​
=2.45m/s2
Now, find the tension: T=5a+9.8
=5×2.45+9.8
=12.25+9.8
=22.05N



Example 3

Two blocks, A and B, with masses 4kg and 6kg, are connected by a string over a frictionless pulley. Block A is on an inclined plane with an angle of 30∘ and a coefficient of friction of 0.1. Block B hangs vertically. Find the acceleration and the tension.

mA​=4kg,     mB​=6kg,      θ=30∘,     μ=0.1
For block A on the incline: T−mA​gsinθ−μmA​gcosθ=mA​a
For block B: mB​g−T=mB​a
Combine the equations: T−4×9.8×sin30∘−0.1×4×9.8×cos30∘=4a T−19.6−3.39=4a T−22.99=4a

T−19.6−3.39=4a T−22.99=4a
6 ×9.8−T=6a
Add the equations: 58.8−22.99=10a 35.81=10a a=3.581m/s2

Find the tension: T=4a+22.99=4×3.581+22.99=14.324+22.99=37.314N



Example 4

A 7 kg block on a frictionless table is connected by a string to a 5 kg block hanging off the table. What is the acceleration of the blocks and the tension in the string?

m1​=7kg,    m2​=5kg
For the block on the table: T=m1​a
For the hanging block: m2​g−T=m2​a
Combine the equations: T=7a 5×9.8−T=5a 49−T=5a

Substitute T:
49−7a=5a
49=12a
a=1249​
=4.083m/s2
Find the tension: T=7a=7×4.083
=28.581N



Example 5

Two blocks, each of mass 3kg, are connected by a string over a pulley. One block is on a frictionless incline of 45∘, and the other hangs vertically. Find the acceleration and tension.

m1​=    m2​=3kg,    θ=45∘
For block on the incline: T−m1​gsinθ=m1​a
T−3×9.8×sin45∘=3a
T−3×9.8×22​​=3a
T−20.79=3a

For the hanging block: m2​g−T=m2​a
3×9.8−T=3a
29.4−T=3a

Add the equations: 29.4−20.79=6a
8.61=6a
a=68.61​
=1.435m/s2
Find the tension: T=3a+20.79=3×1.435+20.79=4.305+20.79=25.095N



Example 6

A 4 kg block is on a table connected by a string to a 2 kg block hanging off the side. If the table has a friction coefficient of 0.3, find the acceleration of the system and the tension in the string.

m1​=4kg,   m2​=2kg,    μ=0.3
For the block on the table: T−μm1​g=m1​a T−0.3×4×9.8=4a T−11.76=4a
For the hanging block: m2​g−T=m2​a 2×9.8−T=2a 19.6−T=2a

Combine the equations: T−11.76=4a
19.6−T=2a