AOS5 Topic 3: Linear Dependence and Independence
A vector \( \mathbf{w} \) is a linear combination of vectors \( \mathbf{v}_1, \mathbf{v}_2, \ldots, \mathbf{v}_n \) if it can be expressed in the form
\[ \mathbf{w} = k_1 \mathbf{v}_1 + k_2 \mathbf{v}_2 + \ldots + k_n \mathbf{v}_n \]for some real numbers \( k_1, k_2, \ldots, k_n \).
Linearly dependent
A set of vectors is said to be linearly dependent if at least one of its members can be expressed as a linear combination of other vectors in the set.
Linearly independent
A set of vectors is said to be linearly independent if it is not linearly dependent.That is, a set of vectors is linearly independent if no vector in the set is expressible as a linear combination of other vectors in the set.
For example, it is easy to show that a set of two non-zero vectors is linearly dependent if andonly if the two vectors are parallel.
We can give a useful alternative description of linear dependence:
Two vectors: A set of two vectors \( \mathbf{a} \) and \( \mathbf{b} \) is linearly dependent if and only if there exist real numbers \( k \) and \( \ell \), not both zero, such that \( k\mathbf{a} + \ell\mathbf{b} = \mathbf{0} \).
Three vectors: A set of three vectors \( \mathbf{a} \), \( \mathbf{b} \), and \( \mathbf{c} \) is linearly dependent if and only if there exist real numbers \( k \), \( \ell \), and \( m \), not all zero, such that \( k\mathbf{a} + \ell\mathbf{b} + m\mathbf{c} = \mathbf{0} \).
In general: A set of \( n \) vectors \( \mathbf{a}_1, \mathbf{a}_2, \ldots, \mathbf{a}_n \) is linearly dependent if and only if there exist real numbers \( k_1, k_2, \ldots, k_n \), not all zero, such that \( k_1\mathbf{a}_1 + k_2\mathbf{a}_2 + \ldots + k_n\mathbf{a}_n = \mathbf{0} \).
Note: Any set that contains the zero vector is linearly dependent. Any set of three or more two-dimensional vectors is linearly dependent. Any set of four or more three-dimensional vectors is linearly dependent.
We will use the following method for checking whether three vectors are linearly dependent.
Linear dependence for three vectors:
Let \( \mathbf{a} \) and \( \mathbf{b} \) be non-zero vectors that are not parallel. Then vectors \( \mathbf{a} \), \( \mathbf{b} \), and \( \mathbf{c} \) are linearly dependent if and only if there exist real numbers \( m \) and \( n \) such that \( \mathbf{c} = m\mathbf{a} + n\mathbf{b} \).
This representation of a vector \( \mathbf{c} \) in terms of two linearly independent vectors \( \mathbf{a} \) and \( \mathbf{b} \) is unique, as demonstrated in the following important result.
Linear combinations of independent vectors:
Let \( \mathbf{a} \) and \( \mathbf{b} \) be two linearly independent (i.e., not parallel) vectors. Then:
\( m\mathbf{a} + n\mathbf{b} = p\mathbf{a} + q\mathbf{b} \) implies \( m = p \) and \( n = q \)Proof:
Assume that \( ma + nb = pa + qb \). Then \( (m - p)a + (n - q)b = 0 \). As vectors \( \mathbf{a} \) and \( \mathbf{b} \) are linearly independent, it follows from the definition of linear independence that \( m - p = 0 \) and \( n - q = 0 \). Hence \( m = p \) and \( n = q \).
Note: This result can be extended to any finite number of linearly independent vectors.
Example 1
Example 2
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Example 3
\( \overrightarrow{XB} = \frac{4}{5} \overrightarrow{DB} = \frac{4}{5} (\overrightarrow{OD} + \overrightarrow{OB}) = \frac{4}{5} (-k\overrightarrow{OA} + \overrightarrow{OB}) = \frac{4}{5}(-ka + b) = -\frac{4k}{5}\vec{a} + \frac{4}{5}\vec{b} \)
\( \overrightarrow{OX} = \frac{2}{5} \overrightarrow{OE} = \frac{2}{5} (\overrightarrow{OA} + \overrightarrow{AE}) = \frac{2}{5} \overrightarrow{OA} + \frac{2}{5} \overrightarrow{AB} = \frac{2}{5}a + \frac{2}{5}\cdot(`b - a) \)
Example 4
\( \overrightarrow{cXB} = \overrightarrow{XO} + \overrightarrow{OB} = -\overrightarrow{OX} + \overrightarrow{OB} = -\frac{2}{5}(1 - `)a - \frac{2}{5}b + b = \frac{2}{5}(` - 1)a + (1 - \frac{2}{5})b \)