U3AOS1 Topic 3: Circular Motion
The distance around a circle is the circumference and is calculated through the following formula
\[ d = \text{circumference} = 2 \pi r \]
Therefore the average speed can be calculated by dividing the distance around the circle by the time it takes
\[ \text{speed}_{avg} = \frac{d}{t} = \frac{2 \pi r}{t} \]
The average velocity will always be 0 since the object returns to its original position (no displacement). However, there is a varying instantaneous velocity since the direction is changing.
The acceleration is calculated through the following formula
\[ a = \frac{v^2}{r} = \frac{4 \pi^2 r}{T} \]
The acceleration always points toward the center of the circle. So the net force is always toward the center of the circle as well.
Using these equations, the force on a mass travelling in circular motion can be calculated by using Newton's Laws.
\[ F_{net} = ma = \frac{mv^2}{r} = \frac{4m \pi^2 r}{T} \]
A key note about circular motion is that the acceleration and the velocity are $ 90$ degrees out of phase. This means that if the velocity at $t = 0$ is to the right then the acceleration would be either up or down depending on the direction it is travelling in. This can be seen in the simulation below.
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